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Linglib.Theories.Pragmatics.NeoGricean.Implementations.BarLevFox2020

Free Choice Configuration #

To derive free choice, we need:

Key observation: This ALT is NOT closed under conjunction!

This non-closure is what allows II to derive free choice.

Possible worlds for free choice (whether each disjunct is permitted).

The separatelyAB world is crucial: it represents an epistemic state where a and b are each individually permitted but not jointly — i.e., some accessible world has a (not b) and some has b (not a), but no single accessible world has both. This distinguishes ◇a ∧ ◇b from ◇(a ∧ b) and is what makes free choice derivable via II.

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      The Key Structural Property #

      Theorem (Non-closure): fcALT is NOT closed under conjunction.

      Specifically: permA ∧ permB (= ◇a ∧ ◇b) is not in fcALT.

      This is the structural property that distinguishes FC alternatives from simple disjunction alternatives and enables the free choice inference.

      For simple disjunction:

      For FC disjunction:

      The free choice alternatives are NOT closed under conjunction in the relevant sense: the conjunction of two alternatives is not equivalent to any single alternative in the general case.

      In modal logic: ◇a ∧ ◇b ⊭ ◇(a ∧ b) (there are worlds where both are individually possible but their conjunction is not).

      IE Computation for Free Choice #

      For φ = ◇(a ∨ b) and ALT = {◇(a ∨ b), ◇a, ◇b, ◇(a ∧ b)}:

      IE Analysis:

      Result: IE = {◇(a ∧ b)}

      This is where standard exhaustivity stops: Exh^{IE}(◇(a ∨ b)) = ◇(a ∨ b) ∧ ¬◇(a ∧ b) which does NOT entail ◇a ∧ ◇b.

      II Computation for Free Choice #

      After IE excludes ◇(a ∧ b), II considers which remaining alternatives can be consistently assigned TRUE.

      II Analysis: Given φ = ◇(a ∨ b) and IE = {◇(a ∧ b)}:

      Consider the constraint set: {◇(a ∨ b), ¬◇(a ∧ b)}

      Therefore: II = {◇a, ◇b}

      Result: Exh^{IE+II}(◇(a ∨ b)) = ◇(a ∨ b) ∧ ¬◇(a ∧ b) ∧ ◇a ∧ ◇b

      This is FREE CHOICE!

      Main Result: Free Choice Derivation #

      Theorem: Exh^{IE+II}(◇(a ∨ b)) ⊢ ◇a ∧ ◇b

      The exhaustified meaning of "you may have a or b" entails "you may have a AND you may have b".

      The free choice inference: exhaustified ◇(a ∨ b) entails ◇a

      The free choice inference: exhaustified ◇(a ∨ b) entails ◇b

      Main Free Choice Theorem: Exh^{IE+II}(◇(a ∨ b)) ⊢ ◇a ∧ ◇b

      Why Simple Disjunction Doesn't Get Free Choice #

      For comparison, simple disjunction:

      This ALT IS closed under conjunction (a ∧ b is already there).

      IE Analysis: IE = {a, b, a ∧ b} (all proper alternatives excludable) II Analysis: II = ∅ (nothing can be consistently included after IE)

      Result: Exh^{IE+II}(a ∨ b) = (a ∨ b) ∧ ¬a ∧ ¬b ∧ ¬(a ∧ b) = ⊥

      This is inconsistent! So Exh cannot apply to simple disjunction (motivating embedded exhaustification in complex sentences).

      The contrast:

      Simple disjunction worlds

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          Simple disjunction IS closed under conjunction (a ∧ b ∈ ALT)

          For simple disjunction, exhaustification yields exclusive-or (or inconsistency without embedded Exh)

          Summary #

          Definitions #

          Results #

          Theoretical Insight #

          The structural difference between FC and simple disjunction is closure under conjunction: