A valuation assigns truth values to atoms. We represent it as the set of atoms that are TRUE.
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A proposition is a set of valuations (the valuations that make it true).
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The atom of a literal.
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Whether a literal is positive.
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The negation of a literal.
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A valuation satisfies a literal.
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V_{-L}: The valuation identical to V except over the atom of L. If L = [p], then V_{-L} has p ∉ V_{-L} iff p ∈ V. If L = [¬p], then V_{-L} has p ∈ V_{-L} iff p ∉ V.
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- Phenomena.ScalarImplicatures.Studies.Spector2007.flipLiteral Atom V L = if h : L.atom ∈ V then Finset.erase V L.atom else Finset.cons L.atom V h
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Definition 2 (Favoring): A proposition P favors a literal L if there exists a valuation V such that:
- V ∈ P (V makes P true)
- L.satisfies V = true (V makes L true)
- flipLiteral V L ∉ P (flipping L makes P false)
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- Phenomena.ScalarImplicatures.Studies.Spector2007.favors Atom P L = ∃ V ∈ P, L.satisfies V = true ∧ Phenomena.ScalarImplicatures.Studies.Spector2007.flipLiteral Atom V L ∉ P
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Definition 4 (Positive Proposition): A proposition is positive if it favors at least one positive literal and no negative literal.
"A positive proposition is a proposition that favors no negative literal and is distinct from ⊥ and ⊤."
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A proposition is negative if it favors at least one negative literal and no positive literal.
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V' is a proper subset of V (as sets of true atoms).
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- Phenomena.ScalarImplicatures.Studies.Spector2007.properSubset Atom V' V = (V' ⊂ V)
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Definition 6 (Exhaustification): The set of minimal valuations in P.
Exhaust(P) = {V ∈ P | ¬∃V' ∈ P, V' ⊂ V}
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Definition 5 (Positive Extension): The upward closure of P.
Pos(P) = {V | ∃V' ∈ P, V' ⊆ V}
"For any non-negative proposition P, there is a unique positive proposition Q such that P entails Q and Q entails all other positive propositions that P entails."
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- Phenomena.ScalarImplicatures.Studies.Spector2007.Pos Atom P = {V : Phenomena.ScalarImplicatures.Studies.Spector2007.Valuation Atom | ∃ V' ∈ P, V' ⊆ V}
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Helper: If P is positive and W ∈ P and a ∉ W, then W ∪ {a} ∈ P. (Otherwise P would favor [¬a].)
Helper: Positive propositions are upward closed (if V' ⊆ V and V' ∈ P, then V ∈ P). Proved by strong induction on |V \ V'| (the "gap" between V' and V).
Fact 1: If P is positive, then Pos(P) = P.
"If P is positive, Pos(P) = P"
Fact 2: Pos(Exhaust(P)) = Pos(P).
"Pos(Exhaust(P)) = P" [when P is positive, this is Pos(P)]
An information state is itself a proposition (set of valuations the speaker considers possible).
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Definition 3 (Optimal States): I(P) is the set of information states where P is the strongest positive proposition entailed.
I(P) = {i | Pos(i) = P}
An information state i makes P optimal iff P is the strongest positive proposition that i entails.
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Definition 4 (Maximal Optimal States): Max(P) is the set of maximal elements of I(P) - the most informed states that still make P optimal.
"Max(S, α, Q) = {i | i ∈ I(S, α, Q) and ∀i' (i' ∈ I(S, α, Q)) → ¬(i'/Q ⊂ i/Q)}"
In our setting: Max(P) = {i ∈ I(P) | ∀i' ∈ I(P), ¬(i' ⊂ i)}
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Exhaust(P) is in I(P) for positive P.
Since Pos(Exhaust(P)) = Pos(P) = P (by Facts 1 and 2), Exhaust(P) is an information state that makes P optimal.
Exhaust(P) entails all members of I(P).
"We want to show that Exhaust(P) entails all the other members of I(P)."
@cite{spector-2007}:
For any positive proposition P, Max(P) = {Exhaust(P)}.
"Theorem: if P is a positive proposition, then Max(P) = {Exhaust(P)}, and therefore P implicates Exhaust(P)."
This derives exhaustive interpretation from Gricean reasoning:
- The speaker uttered P (Quality: they believe P)
- P was optimal among alternatives (Quantity: no better option)
- Assuming maximal informativeness → the speaker's state is Exhaust(P)
- Therefore P implicates Exhaust(P)
Example: The proposition "A or B" (at least one of A, B is true).
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- Phenomena.ScalarImplicatures.Studies.Spector2007.orProp Atom A B = {V : Phenomena.ScalarImplicatures.Studies.Spector2007.Valuation Atom | A ∈ V ∨ B ∈ V}
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Example: The exhaustification of "A or B" is "exactly A or exactly B".
This is the minimal exclusive disjunction (singletons only). The more general "A xor B" (A ∈ V ↔ B ∉ V) includes non-minimal sets like {A, C}.
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The exhaustification of "A or B" yields exclusive disjunction (minimal singletons).